Specific Heat Capacity Calculator

Calculate heat energy transferred using Q = mcΔT. Covers water, metals, gases, and all GCSE physics required practical concepts with worked examples.

Q = mcΔT Calculator

Select a material or enter a custom specific heat capacity, then fill in the known values. Leave one field blank to solve for it, or select what you want to calculate.

Quick select a material:

Water4,200 Iron450 Copper390 Aluminium900 Air1,005 Ice2,100 Steel502 Gold128
Q = m × c × ΔT
m = Q ÷ (c × ΔT)
ΔT = Q ÷ (m × c)
c = Q ÷ (m × ΔT)

The Formula: Q = mcΔT

Specific heat capacity (c) is the amount of energy required to raise the temperature of 1 kg of a substance by 1°C (or 1 K). It quantifies how resistant a material is to temperature change.

Q = m × c × ΔT

Key Worked Example: Heat 2 kg of water from 20°C to 100°C:

Q = 2 × 4,200 × (100 − 20) = 2 × 4,200 × 80 = 672,000 J (672 kJ)

This is the energy needed to boil 2 kg (2 litres) of water in a kettle, equivalent to approximately 0.187 kWh of electrical energy.

Specific Heat Capacity of Common Materials

These values are at standard conditions (approximately 25°C, 1 atm). Values can vary slightly with temperature and purity.

Materialc (J/kg°C)Notes
Water (liquid)4,200Highest of common liquids — excellent coolant and climate regulator
Ice2,100Half that of liquid water — used in calorimetry
Steam (water vapour)2,010At 100°C, 1 atm
Air (dry)1,005At constant pressure (Cp)
Aluminium900High for a metal — used in cookware and heat sinks
Glass840Varies with composition
Brick / concrete840Important for thermal mass in buildings
Steel502Common structural metal
Iron450Close to steel
Copper390Low for a common metal — excellent heat conductor
Brass380Copper-zinc alloy
Tin228Low specific heat — heats quickly
Silver235Best electrical conductor but expensive
Gold128Dense metal with low specific heat
Lead128Heavy, low specific heat
Mercury (liquid)140Used in thermometers (increasingly replaced)
Ethanol2,440Common organic solvent
Engine oil1,900Approx. value for mineral oil

Why Water's High Specific Heat Capacity Matters

Water has one of the highest specific heat capacities of any common substance (4,200 J/kg°C). This has profound effects on climate, industry, and biology.

Climate Regulation

Oceans cover 71% of Earth's surface and absorb vast amounts of solar energy without large temperature changes, due to water's high specific heat. This stabilises global temperatures and explains why coastal areas have milder, more temperate climates than inland areas at the same latitude. Compare London (coastal-influenced, average range 5–24°C) with Moscow (continental, −10 to 24°C).

Industrial Cooling

Water is the dominant coolant in power stations, car engines, and industrial processes because it can absorb large quantities of heat for relatively little temperature rise. A car cooling system may circulate 5–8 litres of water (plus antifreeze) to maintain engine temperature. An electric power station may use millions of litres per hour in its cooling towers.

The Human Body

The human body is approximately 60% water by mass. This high water content helps maintain a stable core temperature (37°C), buffering against rapid temperature swings from exercise or ambient temperature changes. Sweating uses water's high latent heat of vaporisation (2,260,000 J/kg) to provide powerful cooling.

Central Heating Systems

Hot water central heating systems exploit water's high specific heat to distribute warmth efficiently around a building. A relatively small volume of hot water can deliver a large amount of thermal energy to radiators. Upgrading insulation reduces the temperature rise required and therefore the energy cost.

Specific Latent Heat

When a substance changes state (e.g., melts or boils), energy is transferred without any temperature change. This is specific latent heat.

Q = m × L  (no temperature change during state change)
SubstanceLatent Heat of Fusion (melting, J/kg)Latent Heat of Vaporisation (boiling, J/kg)
Water334,000 (334 kJ/kg)2,260,000 (2,260 kJ/kg)
Ethanol108,000841,000
Iron247,0006,090,000
Aluminium397,00010,900,000
Nitrogen (liquid)25,700198,000

Example: Melting 1 kg of ice at 0°C requires Q = 1 × 334,000 = 334,000 J (334 kJ) — without any temperature change.

Water's exceptionally high latent heat of vaporisation (2,260 kJ/kg) means sweating is very effective at cooling the body. Evaporating just 100 g of sweat removes 226 kJ of heat energy.

GCSE Required Practical: Specific Heat Capacity

This is a compulsory practical in AQA, OCR, and Edexcel GCSE Physics and Combined Science courses.

Method

Sources of Error and Improvements

Expected Results (Aluminium)

True value: 900 J/kg°C. Typical experimental results: 850–1,050 J/kg°C depending on insulation quality. Percentage error = |experimental − true| ÷ true × 100%.

GCSE Practice Questions

Q1. Calculate the energy needed to heat 3 kg of iron from 20°C to 220°C. (c of iron = 450 J/kg°C)
Q = mcΔT = 3 × 450 × 200 = 270,000 J (270 kJ)
Q2. A 0.5 kg block of copper absorbs 19,500 J of heat energy. If the initial temperature was 25°C, what is the final temperature? (c of copper = 390 J/kg°C)
ΔT = Q ÷ (mc) = 19,500 ÷ (0.5 × 390) = 19,500 ÷ 195 = 100°C. Final temperature = 25 + 100 = 125°C
Q3. In a GCSE practical, 50 J of energy is supplied to 0.1 kg of an unknown metal, raising its temperature by 2.5°C. What is the specific heat capacity of the metal?
c = Q ÷ (mΔT) = 50 ÷ (0.1 × 2.5) = 50 ÷ 0.25 = 200 J/kg°C (closest match: lead or mercury)
Q4. How much energy (in kWh) is needed to heat 200 litres of water from 15°C to 60°C for a domestic hot water system? (1 litre water = 1 kg; c = 4,200 J/kg°C)
Q = 200 × 4,200 × 45 = 37,800,000 J = 37,800 kJ = 10.5 kWh. At 24p/kWh this costs approximately £2.52.

Frequently Asked Questions

What is the formula for specific heat capacity?

The formula is Q = mcΔT, where Q is heat energy in Joules, m is mass in kilograms, c is specific heat capacity in J/kg°C, and ΔT is the temperature change in °C (or K). Rearranging: c = Q ÷ (m × ΔT); m = Q ÷ (c × ΔT); ΔT = Q ÷ (m × c).

What is the specific heat capacity of water and why is it so high?

Water has a specific heat capacity of 4,200 J/kg°C. This is exceptionally high because water molecules form extensive networks of hydrogen bonds. A large amount of energy must be supplied to increase the motion of molecules (and thus temperature) before these bonds are disrupted. This is why the sea heats up and cools down much more slowly than the land.

What is the difference between specific heat capacity and latent heat?

Specific heat capacity (Q = mcΔT) describes energy transfer during a temperature change, with no change of state. Specific latent heat (Q = mL) describes energy transfer during a change of state (melting or boiling), with no temperature change. During melting or boiling, all energy supplied goes into breaking intermolecular bonds rather than increasing molecular kinetic energy (temperature).

What is the GCSE required practical for specific heat capacity?

The required practical involves using an electric immersion heater to heat a block of metal (usually aluminium) or a known volume of water. Energy supplied is measured using Q = VIt or a joulemeter, and temperature rise is recorded with a thermometer or data logger. Specific heat capacity is calculated as c = Q ÷ (mΔT). The main source of error is heat loss to the environment, which causes the calculated value to be higher than the true value.

How do I convert Joules to kilowatt-hours for energy bills?

1 kWh = 3,600,000 J (3.6 MJ). Divide the energy in Joules by 3,600,000 to get kWh. Example: heating 50 litres of water from 20°C to 70°C requires Q = 50 × 4,200 × 50 = 10,500,000 J = 10,500 kJ = 2.917 kWh. At the UK average electricity price of approximately 24p/kWh, this costs about 70p.

Which materials have the lowest specific heat capacity?

Heavy metals generally have the lowest specific heat capacities: gold (128 J/kg°C), lead (128 J/kg°C), mercury (140 J/kg°C), tin (228 J/kg°C). This means they heat up and cool down quickly for a given mass. By contrast, water (4,200 J/kg°C) and alcohols (2,000–2,500 J/kg°C) have very high values and resist temperature changes effectively.

MB
Mustafa Bilgic Written & reviewed by Mustafa Bilgic — physics calculator specialist at UKCalculator.com. Aligned with AQA, OCR, and Edexcel GCSE Physics specifications. Last updated: 20 February 2026.

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