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Equation Solver UK - Linear & Quadratic Equations

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Solve linear and quadratic equations online. Perfect for GCSE and A-Level maths students. Get instant solutions with step-by-step explanations. Updated 2026.

Solve Your Equation

Worked Examples

Example 1: Solving a Linear Equation

Problem: Solve 3x - 9 = 0

Step 1: Identify coefficients
a = 3, b = -9
Step 2: Apply formula x = -b/a
x = -(-9)/3 = 9/3 = 3
Step 3: Check solution
3(3) - 9 = 9 - 9 = 0

Answer: x = 3

Example 2: Quadratic with Two Real Solutions

Problem: Solve x² - 5x + 6 = 0

Step 1: Identify coefficients
a = 1, b = -5, c = 6
Step 2: Calculate discriminant
Δ = b² - 4ac = (-5)² - 4(1)(6) = 25 - 24 = 1
Step 3: Since Δ > 0, two real solutions exist
x = (-b ± √Δ) / 2a = (5 ± 1) / 2
Step 4: Calculate both solutions
x₁ = (5 + 1) / 2 = 3
x₂ = (5 - 1) / 2 = 2

Answer: x = 3 or x = 2

Example 3: Quadratic with One Solution (Perfect Square)

Problem: Solve x² - 6x + 9 = 0

Step 1: Identify coefficients
a = 1, b = -6, c = 9
Step 2: Calculate discriminant
Δ = (-6)² - 4(1)(9) = 36 - 36 = 0
Step 3: Since Δ = 0, one repeated solution
x = -b / 2a = 6 / 2 = 3
Step 4: Recognize as perfect square
(x - 3)² = 0, so x = 3

Answer: x = 3 (repeated root)

Example 4: Quadratic with Complex Solutions

Problem: Solve x² + 2x + 5 = 0

Step 1: Identify coefficients
a = 1, b = 2, c = 5
Step 2: Calculate discriminant
Δ = (2)² - 4(1)(5) = 4 - 20 = -16
Step 3: Since Δ < 0, complex solutions
√(-16) = 4i (where i = √-1)
Step 4: Apply quadratic formula
x = (-2 ± 4i) / 2 = -1 ± 2i

Answer: x = -1 + 2i or x = -1 - 2i

Example 5: Rearranging Before Solving

Problem: Solve 2x² + 3x = 5

Step 1: Rearrange to standard form
2x² + 3x - 5 = 0
Step 2: Identify coefficients
a = 2, b = 3, c = -5
Step 3: Calculate discriminant
Δ = 9 - 4(2)(-5) = 9 + 40 = 49
Step 4: Solve using quadratic formula
x = (-3 ± 7) / 4
x₁ = 4/4 = 1
x₂ = -10/4 = -2.5

Answer: x = 1 or x = -2.5

Tips for Solving Equations

Linear Equations

  • Isolate the variable: Get x by itself on one side
  • Inverse operations: Add to remove subtraction, divide to remove multiplication
  • Check your work: Substitute solution back into original equation
  • Special cases: If a=0, equation may have no solution or infinite solutions

Quadratic Equations

  • Standard form first: Always rearrange to ax² + bx + c = 0
  • Check discriminant: Tells you solution type before calculating
  • Factoring shortcut: If equation factors easily, use that instead
  • Completing the square: Alternative method, especially for perfect squares
  • Sum and product: x₁ + x₂ = -b/a, x₁ × x₂ = c/a (useful for checking)

Common Shortcuts

  • Recognize patterns: (x±a)² = x² ± 2ax + a²
  • Difference of squares: x² - a² = (x+a)(x-a)
  • Calculator check: Use calculator to verify, but show working
  • Graph visualization: Solutions are x-intercepts

Common Mistakes to Avoid

Mistake 1: Sign errors in quadratic formula

WRONG: Forgetting the negative in -b

CORRECT: x = (-b ± √Δ) / 2a, not (b ± √Δ) / 2a

Mistake 2: Forgetting both solutions

WRONG: Only writing x = (-b + √Δ) / 2a

CORRECT: Write both x₁ and x₂ using ± symbol

Mistake 3: Incorrect discriminant

WRONG: Δ = b² - 4c (forgetting a)

CORRECT: Δ = b² - 4ac (include the a!)

Mistake 4: Not rearranging to standard form

WRONG: Trying to solve 2x² = 8 - 3x directly

CORRECT: Rearrange to 2x² + 3x - 8 = 0 first

Mistake 5: Division errors

WRONG: (-b ± √Δ) / 2a = -b/2a ± √Δ/2a

CORRECT: Divide ENTIRE numerator by 2a

Complete Guide to Equation Solving

Understanding Equations

An equation is a mathematical statement that two expressions are equal. Solving an equation means finding all values of the variable that make the equation true. Linear equations have degree 1 (highest power is x¹), while quadratic equations have degree 2 (highest power is x²).

The Quadratic Formula

For any quadratic equation ax² + bx + c = 0 (where a ≠ 0):
x = (-b ± √(b² - 4ac)) / (2a)

This formula works for ALL quadratic equations and is derived by completing the square. Memorize it - it's essential for GCSE and A-Level maths!

The Discriminant Explained

The discriminant Δ = b² - 4ac tells you about solutions BEFORE calculating:

  • Δ > 0: Two different real solutions (parabola crosses x-axis twice)
  • Δ = 0: One repeated real solution (parabola touches x-axis once)
  • Δ < 0: Two complex solutions (parabola doesn't cross x-axis)

Methods for Solving Quadratics

  1. Factoring: Write as (x+p)(x+q)=0, solve x=-p or x=-q. Fast but only works for nice numbers.
  2. Quadratic Formula: Always works! Use when factoring is difficult.
  3. Completing the Square: Rewrite as (x+h)²=k. Good for deriving vertex form.
  4. Graphing: Find x-intercepts. Useful for visualization but not always accurate.

Real-World Applications

  • Projectile motion: Height equations are quadratic (h = -5t² + vt + h₀)
  • Area problems: Finding dimensions when area is known
  • Economics: Profit maximization, break-even analysis
  • Physics: Acceleration, energy equations
  • Engineering: Structural design, optimization

Frequently Asked Questions

How do you solve a quadratic equation?

Use the quadratic formula: x = (-b ± √(b²-4ac)) / (2a). First calculate the discriminant (b²-4ac). If positive, you get two real solutions. If zero, one solution. If negative, two complex solutions. Always show your working and check solutions by substituting back.

What is a linear equation?

A linear equation has the form ax + b = 0, where a and b are constants and a ≠ 0. Solve by rearranging: x = -b/a. Linear equations always have exactly one solution and graph as straight lines.

What are complex solutions?

Complex solutions occur when the discriminant is negative. They involve imaginary numbers (i, where i² = -1). Written as a + bi, where a is the real part and b is the imaginary part. Complex solutions always come in conjugate pairs for equations with real coefficients.

Can this solver help with GCSE maths?

Yes! This equation solver is perfect for GCSE and A-Level students. It solves quadratic equations taught in GCSE maths and shows the discriminant, which is important for understanding solution types. Use it to check homework and understand step-by-step solutions.

What if coefficient 'a' is zero?

If a = 0 in a quadratic equation, it becomes linear (bx + c = 0). If a = 0 in a linear equation, the equation has no solution (if b ≠ 0) or infinitely many solutions (if b = 0 too).

How do I check my answer is correct?

Substitute your solution(s) back into the original equation. If the left side equals the right side, your answer is correct. For quadratic equations, check BOTH solutions if there are two.

Is this calculator free?

Yes! Completely free with no signup required. Unlimited calculations for homework, revision, and exam preparation. Works on phones, tablets, and computers.

What's the difference between roots, solutions, and zeros?

These terms mean the same thing! "Solutions" and "roots" refer to the values of x that satisfy the equation. "Zeros" refers to where the graph crosses the x-axis (y=0). All three terms are used interchangeably in maths.

Equation Rearranger: Make X the Subject

Rearranging an equation means isolating a particular variable on one side. The golden rule is: whatever you do to one side, you must do to the other side. This tool and guide covers the most common equation rearrangement techniques used in GCSE and A-Level maths, physics, and chemistry.

How to Make X the Subject — Step-by-Step Method

  1. Identify what you want to isolate — decide which variable you want to make the subject.
  2. Move all terms containing x to one side — use addition or subtraction to move other terms to the opposite side.
  3. Simplify — collect like terms and simplify coefficients.
  4. Divide or multiply — divide both sides by the coefficient of x to isolate it.
  5. Apply inverse operations — undo squares with square roots, undo logarithms with exponentials, etc.
  6. Check your answer — substitute back into the original equation to verify.

Worked Examples: Make X the Subject

Example 1: Make x the subject of y = mx + c

Start with: y = mx + c
Step 1: Subtract c from both sides → y − c = mx
Step 2: Divide both sides by m → (y − c) / m = x
x = (y − c) / m

Example 2: Make x the subject of v = u + at (rearrange for a)

Start with: v = u + at
Step 1: Subtract u from both sides → v − u = at
Step 2: Divide both sides by t → (v − u) / t = a
a = (v − u) / t

Example 3: Make x the subject of A = πr² (rearrange for r)

Start with: A = πr²
Step 1: Divide both sides by π → A / π = r²
Step 2: Take the square root of both sides → √(A / π) = r
r = √(A / π)

Example 4: Make x the subject of ax² + bx + c = 0 (quadratic formula)

Start with: ax² + bx + c = 0
Step 1: Subtract c: ax² + bx = −c
Step 2: Divide by a: x² + (b/a)x = −c/a
Step 3: Complete the square: (x + b/2a)² = (b² − 4ac) / 4a²
Step 4: Take square roots and rearrange
x = (−b ± √(b² − 4ac)) / (2a)

Equation Rearranger Reference Table

Common physics, maths, and science formulas rearranged. Use these as a quick reference for GCSE and A-Level. Click the formula to copy.

Formula Type Original Formula Rearranged For Result
Lineary = mx + cxx = (y−c)/m
Speed (SUVAT)v = u + ataa = (v−u)/t
Speed (SUVAT)v = u + attt = (v−u)/a
Circle areaA = πr²rr = √(A/π)
Volume boxV = lwhll = V/(wh)
Energy (E=mc²)E = mc²mm = E/c²
Ohm's LawV = IRRR = V/I
Ohm's LawV = IRII = V/R
ForceF = mamm = F/a
DensityD = m/VVV = m/D
PressureP = F/AAA = F/P
Kinetic energyKE = ½mv²vv = √(2KE/m)
Profit marginP% = (P/C)×100CC = P×100/P%

Expand and Factorise Brackets

Expanding brackets is a fundamental algebraic skill. The key rule is to multiply each term inside the bracket by the term outside (or by each term in the other bracket). This section covers the most common types encountered in GCSE maths, including examples like expand 3(x+4) and (x+3)(x+4).

Single Bracket Expansion

Multiply every term inside the bracket by the factor outside:

Expand 3(x + 4)

Step 1: Multiply 3 × x = 3x
Step 2: Multiply 3 × 4 = 12
3(x + 4) = 3x + 12

Expand −2(x − 5)

Step 1: −2 × x = −2x
Step 2: −2 × (−5) = +10 (negative × negative = positive)
−2(x − 5) = −2x + 10

Double Bracket Expansion (FOIL Method)

The FOIL method (First, Outer, Inner, Last) is the standard technique for multiplying two brackets:

  • First — multiply the first terms of each bracket
  • Outer — multiply the outer terms
  • Inner — multiply the inner terms
  • Last — multiply the last terms of each bracket

Expand (x + 3)(x + 4)

First: x × x = x²
Outer: x × 4 = 4x
Inner: 3 × x = 3x
Last: 3 × 4 = 12
Collect like terms: x² + 4x + 3x + 12 = x² + 7x + 12
(x + 3)(x + 4) = x² + 7x + 12

Expand (x + 3)(x − 5)

First: x × x = x²
Outer: x × (−5) = −5x
Inner: 3 × x = 3x
Last: 3 × (−5) = −15
Collect like terms: x² − 5x + 3x − 15 = x² − 2x − 15
(x + 3)(x − 5) = x² − 2x − 15

Common Expansion Patterns

Expression Expanded Form Pattern Name
(x + a)²x² + 2ax + a²Perfect square (positive)
(x − a)²x² − 2ax + a²Perfect square (negative)
(x + a)(x − a)x² − a²Difference of two squares
(x + a)(x + b)x² + (a+b)x + abGeneral FOIL
a(b + c + d)ab + ac + adDistributive law
(2x + 3)²4x² + 12x + 9Perfect square (numeric)
(x+3)(x+4)(x+5)Expand two brackets first, then thirdTriple bracket

Equation Rearranger: Frequently Asked Questions

How do I rearrange a formula?

To rearrange a formula, perform the same inverse operation on both sides. To isolate x: move all terms not containing x to the other side using addition or subtraction, then divide (or multiply) both sides by x's coefficient. For squared terms, take the square root of both sides at the end. Always check your rearranged formula by substituting numbers back in.

What is the equation rearranger formula?

There is no single “rearranger formula” — different equation types require different techniques. For linear equations (y = mx + c), rearranging for x gives x = (y−c)/m. For quadratic equations, the quadratic formula x = (−b ± √(b²−4ac)) / (2a) is the universal rearrangement. The reference table above covers the most common formulas from physics, chemistry, and maths.

How do you make x the subject of a formula?

Making x the subject means isolating x on the left-hand side of the equation. The steps are: (1) add or subtract terms to collect all x terms on one side; (2) expand any brackets containing x; (3) factorise if x appears more than once; (4) divide both sides by x's coefficient. For example, to make x the subject of 3x + 7 = y: subtract 7 to get 3x = y−7, then divide by 3 to get x = (y−7)/3.

How do you expand brackets?

To expand brackets, multiply each term inside the bracket by the factor outside. For a single bracket: a(b + c) = ab + ac. For double brackets (FOIL method): (x+3)(x+4) = x² + 4x + 3x + 12 = x² + 7x + 12. Remember to pay attention to signs — a negative multiplied by a negative gives a positive.

What does x² + 5x + 6 factorise to?

x² + 5x + 6 factorises to (x + 2)(x + 3). To check: expand using FOIL: x² + 3x + 2x + 6 = x² + 5x + 6. When factorising a quadratic x² + bx + c, find two numbers that multiply to c and add to b. Here, 2 × 3 = 6 and 2 + 3 = 5.

How do you solve x² + 3x − 5 = 0 (written as “x 3 x 5 2”)?

For x² + 3x − 5 = 0, use the quadratic formula with a=1, b=3, c=−5. Discriminant = 3² − 4(1)(−5) = 9 + 20 = 29. Solutions: x = (−3 ± √29) / 2. This gives x ≈ 1.193 or x ≈ −4.193. Use our equation solver above to calculate this instantly with full step-by-step working.

What is an algebraic equation calculator used for?

An algebraic equation calculator solves equations for an unknown variable. Common uses include: solving linear equations (ax + b = 0), solving quadratic equations (ax² + bx + c = 0), rearranging formulas to make a specific variable the subject, expanding and factorising brackets, and verifying homework and exam answers. This calculator is used by GCSE and A-Level students across the UK.

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