Q = mcΔT Calculator

Q = m × c × ΔT

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J/kg·K
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Specific Heat Capacities of Common Materials

Click a material to auto-fill the specific heat capacity value.

Materialc (J/kg·K)Notes
4,186Highest of common liquids; used as coolant
2,010Lower than liquid water
2,080At 100°C and 1 atm
449Commonly used in GCSE practical experiments
385Good electrical and thermal conductor
897Lightweight; used in aircraft and radiators
840Approximate value for soda-lime glass
235Excellent thermal conductor
128Dense; low specific heat capacity
130Very dense; low specific heat capacity
500Varies with form of carbon
700Important for building thermal mass
1,700Varies with moisture content
1,005At constant pressure (Cp)
2,200Common lab solvent

Specific Heat Capacity: Complete UK Physics Guide

Specific heat capacity is a fundamental concept in GCSE and A-Level Physics. It measures how much energy is required to raise the temperature of one kilogram of a substance by one degree Celsius (or one Kelvin). Understanding this property is essential for explaining everyday phenomena from cooking and climate to industrial engineering and refrigeration.

The Q = mcΔT Formula Explained

The equation Q = mcΔT is one of the most important formulas in thermal physics:

  • Q = heat energy transferred (joules, J)
  • m = mass of the substance (kilograms, kg)
  • c = specific heat capacity (joules per kilogram per kelvin, J/kg·K)
  • ΔT = change in temperature (degrees Celsius or Kelvin, °C or K)

Note that a change of 1°C is equal to a change of 1 K, so the two units are interchangeable in ΔT calculations. The formula can be rearranged to find any of the four quantities:

  • To find c: c = Q / (m × ΔT)
  • To find m: m = Q / (c × ΔT)
  • To find ΔT: ΔT = Q / (m × c)

Worked Example: Heating Water

How much energy is needed to heat 2 kg of water from 20°C to 100°C?

  • m = 2 kg, c = 4,186 J/kg·K, ΔT = 100 - 20 = 80 °C
  • Q = m × c × ΔT = 2 × 4,186 × 80 = 669,760 J = 669.76 kJ

This means approximately 670 kJ of thermal energy is needed - equivalent to running a 1 kW kettle for about 670 seconds (11 minutes).

Why Different Materials Have Different Specific Heat Capacities

Specific heat capacity depends on the molecular structure of a substance. Materials with strong intermolecular bonds or complex molecular structures typically require more energy to change temperature. Water has an exceptionally high specific heat capacity (4,186 J/kg·K) due to extensive hydrogen bonding between water molecules. Metals like copper (385 J/kg·K) have lower values because their metallic bonding and free electron structure allows energy to be distributed without large temperature changes.

Practical Applications

Specific heat capacity has numerous real-world applications relevant to GCSE and A-Level Physics:

  • Heating systems: Water is used in central heating radiators because it can store large amounts of energy and release it slowly.
  • Engine cooling: Car cooling systems use water because of its high c value, which prevents engines from overheating.
  • Climate regulation: The high specific heat capacity of seawater moderates coastal temperatures, preventing extreme hot and cold.
  • Cooking: Metals have low c values, heating up quickly, making them suitable for pans and cooking equipment.
  • Hot water bottles: Water retains heat for long periods, making it ideal for warmth storage.

GCSE Required Practical: Specific Heat Capacity

The required practical experiment for GCSE Physics involves measuring the specific heat capacity of a solid material (commonly aluminium). The procedure is:

  1. Measure the mass of the material using an accurate balance.
  2. Insert an electric heater and thermometer into pre-drilled holes in the block.
  3. Wrap the block in insulating material to minimise heat loss.
  4. Record the initial temperature, then switch on the heater.
  5. Record energy supplied (from a joulemeter or by calculating P × t) and temperature change.
  6. Calculate c = Q / (m × ΔT) and compare with the accepted value.

Common sources of error include heat loss to surroundings, which causes the measured c to be higher than the accepted value. Good experimental technique and insulation improve accuracy.

Energy Storage and Thermal Efficiency

Materials with high specific heat capacity make excellent thermal energy stores. This is relevant to A-Level Physics topics including thermodynamics and energy efficiency. The thermal energy store of an object is given by: Thermal energy = mass × specific heat capacity × temperature rise. Increasing the mass or specific heat capacity of a material increases the energy it can store for a given temperature change.

Frequently Asked Questions

What is the formula for specific heat capacity?

The formula is Q = mcΔT, where Q is heat energy in joules (J), m is mass in kilograms (kg), c is specific heat capacity in J/kg·K, and ΔT is the temperature change in °C or K. Rearrange to find any variable: c = Q/(mΔT), m = Q/(cΔT), ΔT = Q/(mc).

What is the specific heat capacity of water?

Water's specific heat capacity is 4,186 J/kg·K (often rounded to 4,200 J/kg·K in GCSE). This is unusually high due to hydrogen bonding between water molecules, making water an excellent coolant and thermal buffer in both engineering and climate systems.

Why is specific heat capacity important in GCSE Physics?

It is a core GCSE Physics topic (AQA, OCR, Edexcel) because it explains why materials heat up at different rates. It is required for energy calculations, heating system design, climate science, and all thermal energy transfer topics. Students must apply Q = mcΔT in multi-step calculations.

How do you measure specific heat capacity experimentally?

Use an electric heater in a known mass of material. Measure the energy supplied (Q = Power × time, or use a joulemeter) and the temperature rise. Then calculate c = Q / (m × ΔT). Wrap the sample in insulation to reduce heat loss errors.

What is the difference between heat capacity and specific heat capacity?

Heat capacity (C, in J/K) is for a specific object and depends on its mass. Specific heat capacity (c, in J/kg·K) is a material property, independent of mass. Specific heat capacity = Heat capacity / mass, or C = mc.

Why does water have such a high specific heat capacity?

Water's high c value (4,186 J/kg·K) results from extensive hydrogen bonding between H2O molecules. These bonds require significant energy to disrupt, meaning much heat is needed for a small temperature rise. This gives water its exceptional heat-storing properties used in cooling systems, climate regulation, and everyday applications.

How do you convert between joules and kilojoules in heat calculations?

Divide joules by 1,000 to get kilojoules (1 kJ = 1,000 J). Always ensure mass is in kg (divide grams by 1,000) before substituting into Q = mcΔT. The formula gives Q in joules when m is in kg, c is in J/kg·K, and ΔT is in °C or K.

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Mustafa Bilgic
Physics & Science Calculator Specialist at UK Calculator. Focused on building accurate, curriculum-aligned tools for UK GCSE and A-Level students.
Last updated: February 2026